two opposite angle of a parallelogram are (3x-2)° and (50-x)°. find the measure of each angle
Answers
(3x-2)° = (50-x)° (opp. angles of a llgm are equal)
3x + x = 50 +2
4x = 52
x = 52/4
x = 13
angle 1 (3x-2)° = 3×13-2 =37
angle 2 (50-x)° = 50-13 = 37
GIVEN :-
★ Two oppositeive angles of a parallelogram are (3x - 2)° and (50 - x)°.
TO FIND :-
★ The measure of each angle of parallelogram.
SOLUTION :-
As we knowo that, In parallelogram the opposite angles and opposite sides are equal. So by using this we have,
⇒ (3x - 2)° = (50 - x)°
⇒ 3x + x = 50 + 2
⇒ 4x = 52
⇒ x = 52/4
⇒ x = 13
Now , we got the value of x as 13 , So now by using the value of x we can find the measure of each angle of parallelogram.
⇒ (3x - 2)° = (3 × 13 - 2)° = (39 - 2)° = 37°.
⇒ (50 - x)° = (50 - 13)° = 37°.
Hence two opposite angle of parallelogram are 37° each
Now as we know that sum of adjacent angles of parallelogram is 180°.
⇒ 180° - 37°
⇒ 143°.
Hence other two opposite angle of parallelogram are 143° each.
Hence each angle of parallelogram are 37°, 37°, 143°, 143°.