Math, asked by khushi958333, 6 months ago

two opposite angle of a parallelogram are (3x-2)° and (50-x)°. find the measure of each angle

Answers

Answered by Anjali58301
1

(3x-2)° = (50-x)° (opp. angles of a llgm are equal)

3x + x = 50 +2

4x = 52

x = 52/4

x = 13

angle 1 (3x-2)° = 3×13-2 =37

angle 2 (50-x)° = 50-13 = 37

Answered by prince5132
7

GIVEN :-

★ Two oppositeive angles of a parallelogram are (3x - 2)° and (50 - x)°.

TO FIND :-

★ The measure of each angle of parallelogram.

SOLUTION :-

As we knowo that, In parallelogram the opposite angles and opposite sides are equal. So by using this we have,

(3x - 2)° = (50 - x)°

⇒ 3x + x = 50 + 2

⇒ 4x = 52

⇒ x = 52/4

x = 13

Now , we got the value of x as 13 , So now by using the value of x we can find the measure of each angle of parallelogram.

(3x - 2)° = (3 × 13 - 2)° = (39 - 2)° = 37°.

(50 - x)° = (50 - 13)° = 37°.

Hence two opposite angle of parallelogram are 37° each

Now as we know that sum of adjacent angles of parallelogram is 180°.

⇒ 180° - 37°

143°.

Hence other two opposite angle of parallelogram are 143° each.

Hence each angle of parallelogram are 37°, 37°, 143°, 143°.

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