two opposite angle of a parallelogram are (5 x - 20)° and (70 - 4 x)° find the measurement of each angle of the parallelogram
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sum of all angles of a parallelogram is 360°
(5 x - 20° )° + ( 70 - 4x)° are two angles there apposite angles are equal
2(5x-20)° + 2(70-4x)° =360°
(10x - 40)° + ( 140-8x)° = 360°
10x - 40 + 140 - 8x = 360 °
2x +100= 360°
2x= 260
x = 130°
(5 x - 20° )° + ( 70 - 4x)° are two angles there apposite angles are equal
2(5x-20)° + 2(70-4x)° =360°
(10x - 40)° + ( 140-8x)° = 360°
10x - 40 + 140 - 8x = 360 °
2x +100= 360°
2x= 260
x = 130°
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