Question

two opposite angles of a parallelogram are (3m-2)° and (68-2m)°.find all the angles of a parallelogram​

Answer 1

Answer: 140°, 40°, 140°, 40°

Step-by-step explanation:

Let ABCD be the required parallelogram.

Since it is a parallelogram the opposite angles are equal.

So:

3m-2 = 68-2m

5m = 70

m = 14°

So two angles are 40° and 40°.

Since another pair of opposite angles are equal

A° + B° + C° + D° =360° ( angle sum property)

B° + C° = 360° - 80° = 280°

SINCE ANGLE B AND ANGLE C ARE EQUAL DUE TO OPPOSITE ANGLE

B° = C° = 140°

Therefore angles of the parallelogram are 140° , 40° , 140°, 40°.