Question

two opposite angles of a parallelogram are (3x-2)° and (50-x)°.find the measure of each angle of the parallelogram.

Answer 1

We Know That the opposite angles in a parallelogram are equal. 
Therefore, 
(3x-2)°=(50-x)°
3x-2=50-x
3x+x=50+2
  4x  = 52
     x = 52/4
     x= 13

One Angle= (3x-2)= (3*13-2)= 37°

Since the angles are equal the other angle is also 37°

Answer 2

Ist opposite angle =(3x-2)°
llnd opposite angle =(50-x)°

ATQ,
(3x-2)°=(50-x)°(opp. angles of llgm are equal)
3x+x=50+2
4x=52
x=52/4
x=13°

Thus,
Ist angle =(3x-2)=(3×13-2) =(39-2) =37°
llnd angle =(180-37)=143°
lllrd angle =(50-x)=(50-13)=37°
lVth angle =(180-37)=143°

Hope it will help u...