Two opposite angles of a parallelogram are( 3x-2) and (50-x). Find the measurment of each angle of the parallelogram
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since opposite anopposite angles of a parallelogram is equal is therefore
3x-2=50-x
3x+x = 50+2
4x =52
x= 52/4
x= 13
hence
1st angle = 3*13-2 = 39-2= 37°
2nd angle = 180-37 =147°
3rd angle. = 50-13 = 37°
4th angle = 180-37 = 147°
Hope you solve problem
3x-2=50-x
3x+x = 50+2
4x =52
x= 52/4
x= 13
hence
1st angle = 3*13-2 = 39-2= 37°
2nd angle = 180-37 =147°
3rd angle. = 50-13 = 37°
4th angle = 180-37 = 147°
Hope you solve problem
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