Question

Two opposite angles of a parallelogram are (4x–20)0 and (40–x)0. Find the value of x.​

Answer 1

$(4x - 20) \degree \: and \: (40 - x) \degree$

$To \: find = \geqslant x$

$= \geqslant (4x + x) = (40 + 20)$

$= \geqslant 4x = 60$

$= \geqslant x = \frac{60}{4}$

$= \geqslant x = 15$

$\geqslant Verified\leqslant$

Answer 2

Given:

Two opposite angles of a parallelogram are (4x - 20)° and (40 - x)°.

To find:

The value of x.

Solution:

The value of x is 12°.

To answer this question, first of all, we should know that in a parallelogram ABCD having angles angle A, angle B, angle C and angle D, the opposite angles are equal.

This means,

$angle \: A = angle \: C$

and,

$angle \: B = angle \: D$

So,

according to the question, we have,

the opposite angles of a parallelogram are (4x - 20)° and (40 - x)°.

So,

These angles will be equal.

Thus, we have,

$4x - 20 = 40 - x$

On solving, we have,

$5x = 60$

$x = 12$

Hence, the value of x is 12°.