Math, asked by dkhs, 12 hours ago

Two opposite angles of a parallelogram are (5x – 21)º and (x + 75)°. Find the measure of each of the angles
of the parallelogram.
Help me please

Answers

Answered by Choudharipawan123456
2

Here, it is given that the two opposite angles are

(5x-21)^o and (x+75)^o

As we know that, in a parallelogram the opposite sides are parallel and the opposite angles are equal.

Let four angles of parallelogram will be ∠A, ∠B, ∠C and∠D respectively

=>(5x-21)=(x+75)

=>4x=96

=>x=24^o

So, one of the angles is (5x-21)^o

=>[(5\times 24)-21]\\=>99^o

Therefore, ∠A =C =99^o

We know that in a parallelogram two adjacent sum of an angles is 180^o

=>A +B =180

=>99+B =180

B =81=D (Opposite angles are equal)

Hence, the four angles are 99^o,81^o,99^o,81^o

Answered by syedtahir20
1

As we know that,

Given:

Two opposite angles of a parallelogram are(5x21)º and(x+75).

Find out:

Find the measure of each of the angles  of the parallelogram.

 

Let us:

Two opposite angles of a parallelogram are(5x-21)º and(x + 75)°.

In a parallelogram the opposite sides are parallel.

The opposite angles are equal.

so,

four angles of parallelogram will be ∠A, ∠B, ∠C, and ∠D respectively.

(5x-21)=(x+75)

4x=96

x=24

one of the angles is(5x-21)

(5×24)-21

=99º

Therefore,

A=C=99º

In a parallelogram two adjacent sum of an angle is 180º

A+B=180º

99+B=180º

B=81=D

opposite angles are equal.

So the  each of the angles  of the parallelogram are,

99º,81º,99º,81º

Similar questions