Question

Two opposite angles of a parallelogram att(3x-3)° and (50-x)°.find the measure of each angle of the parallelogram

Answer 1

Hey mate........

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Here is the answer to that question.....

The two Angles add up to 180'

$(3x - 3) + (50 - x) = 180 \\ 2x + 47 = 180 \\ 2x = 133 \\ x = \frac{133}{2} \\ = 66.5 \\ \\ first \: angle \\ = 3x - 3 \\ = 66.5 \times 3 - 1 \times 3 \\ = 3(66.5 - 1) \\ = 56.5 \times 3 \\ = 169.5$
Hope this helps