Question

Two opposite vertices of a square are (3, 2)
and (7,6). Find the co-ordinates of other vertices​

Answer 1

Answer:

Let ABCD be a square and A (–1, 2) and C (3, 2) be the given vertices. Let the coordinates of vertex B be (x, y). Thus, the other two vertices of the square ABCD are (1, 4) and (1, 0).

hope it helps you

Answer 2

Answer:

So B is (3+4,2+0) or (7,2)

similarly D is (3+0,2+4) or (3,6)

Step-by-step explanation

As per in the fig

ABCD is square ,Opposite corners A and C are

A(3,2) and C(7,6)

So AC=√(7-3)² +(6-2)²

=√4²+4²

=4√2

We know that diagonal =side√2

thus side=4 unit

So B is (3+4,2+0) or (7,2)

similarly D is (3+0,2+4) or (3,6)