Question

Two or more bulbs are said to be connected in series iſ the current flowing through one also flows
through the rest. The potential difference across the combination of bulbs connected in series is equal
to the sum of potential differences across the individual bulbs. So, The potential difference across each
bulb is directly proportional to its resistance. On the other hand, if bulbs are connected in parallel, the
potential difference across each bulb is same and the total current flowing through the parallel
combination is equal to the sum of currents passing through the individual bulbs. So, The current flow
through each bulb is inversely proportional to its resistance. Whether the bulbs are connected in series
or in parallel, the brightness of a bulb is more if the power consumed by it is more and vice-versa. The
power consumed by a bulb is given by, P = VI = FR = V?/R , where R is the resistance of the bulb, V
is the potential difference across the bulb and I is the flow of current through it.
If two tungsten bulbs with resistance R, and R, (R, > R, ) respectively are connected first in parallel
and then in series, in a lighting circuit across a battery ; then
1.(d) If, in the parallel combination, the bulb of resistance R2, burns out and the bulb of resistance R1 alone is plugged in: what will be the impact on the net brightness?
(1) Brightness will remain same.
(2) Brightness will increase
(3) Brightness will reduce to zero.
(4) Brightness will decrense​

Answer 1

Answer:

Brightness will remain same.