Question

Two organic compounds,one present in vinegar and the other present in sour milk has empirical formula CH2O. molar mass of A=90g/mol,molar mass of B=60g/mol. calculate the molecular formula of A and B?​

Answer 1

Explanation:

Given -

• Two organic compound, one present in vinegar and other present in sour milk has empirical formula CH2O
• Molar mass of A is 90 g/mol
• Molar mass of B is 60 g/mol

To Find -

• Calculate the molecular formula of A and B

Let's calculate empirical mass first

→ 12 + 1×2 + 16

→ 30 g/mol

Now,

As we know that :-

• Molecular mass = n × empirical mass

For compound A :-

It is given that compound A has molecular mass 90 g/mol And empirical formula is 30 g/mol (calculated above)

Then,

→ 90 = n × 30

→ n = 3

For compound B :-

It is given that compound A has molecular mass 60 g/mol And empirical formula is 30 g/mol (calculated above)

Then,

→ 60 = n × 30

→ n = 2

Now,

As we know that :-

molecular formula = n × Empirical formula

Molecular formula of Compound A :-

→ 3(CH2O)

→ C3H6O3

And

Molecular formula of compound B :-

→ 2(CH2O)

→ C2H4O2

Hence,

Molecular formula of A is C3H6O3

and

Molecular formula of B is C2H4O2.