Two out of six computers in a lab have problems with hard drives. If three computers are selected at random for inspection, what is the probability that none of them has hard drive problems?
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3 are selected at random
4 are not effected
there are 6 computers
probability is 4/6=2/3=0.67
4 are not effected
there are 6 computers
probability is 4/6=2/3=0.67
umaimarahman:
Just found out the answer. No its not 0.5
it is 6C3/4C3 = 0.2
*4C3/6C3 rather
oh sorry
2nd step is wrong
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