Question

Two oxides of a metal contain 50%
and 40% metal M respectively. If the
formula of the first oxide is MO2, the
formula of the second oxide will be.
(A) Mo,
(B) MO
(C) M.O
(D) MO​

Answer 1

Answer:

MO2 is 50% M,

M/(M+32) = 0.5

M = 0.5M + 16

0.5M = 16

So M = 32

32/(32+48) = 32/80 =

32/(32 + 16n) = 0.4

32 = 0.4(32 + 16n) = 12.8 + 6.4n

n = (32-12.8)/6.4 = 19.2/6.4 = 3

So the formula for the 40% M is MO3

Explanation: