Question

Two oxides of a metal contains 50% and 40% of the metal respectively the formula of the first oxide is and MO then the formula of II oxide is

Answer 1

Let Metal in first oxide = x

Oxygen in first oxide= y

Metal in first oxide= 50%

Ratio of metal : oxide = x:y = 1 : 1  ,  Formula given = MO2

Means 2 Oxygen have 50% contribution.

In second Oxide, Metal = 40%

So, Ratio of metal : oxygen = 40 : 60  = 2 : 3
i.e  M2O3

Answer according to the given question would be=  M2O3.

But, I think there is some mistake in question.

The Formula given for the first oxide must be MO.

So that the formula of second oxide will be M2O3.

Answer 2

Let Metal in first oxide = x

Oxygen in first oxide= y

Metal in first oxide= 50%

Ratio of metal : oxide = x:y = 1 : 1  ,  Formula given = MO2

Means 2 Oxygen have 50% contribution.

In second Oxide, Metal = 40%

So, Ratio of metal : oxygen = 40 : 60  = 2 : 3
i.e  M2O3

Answer according to the given question would be=  M2O3.


The Formula given for the first oxide must be MO.

So that the formula of second oxide will be M2O3

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