Two oxides of lead were separately reduced to metallic lead by heating in a current of hydrogen and the following data obtained: 1) mass of yellow oxide taken= 3.45 g, Loss in mass during reduction = 0.24 g 2) mass of brown oxide taken=1.227g, Loss in mass during reduction = 0.16 g Show that the above data illustrate the Law of multiple proportions.
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Answer: Assume mass of oxygen 1 gm
Mass of lead obtained from yellow oxide=3.45 g- 0.24 g = 3.21 g.
Mass of oxygen = 0.24 g.
The mass of lead that combines with 0.24 g of oxygen = 3.21 g.
Hence,mass of lead that combines with 1 g of oxygen = 3.21/0.24=13.4 g
Mass of lead obtained from brown oxide = 1.227 g - 0.16 g =1.067
Mass of Oxygen = 0.16 g.
The mass of lead that combines with 0.16 g of oxygen = 1.067 g.
Hence,mass of lead that combines with 1 gm oxygen=1.067/0.16 =6.66 g.
Now,ratio of masses of lead which combines with a fixed mass of oxygen =13.4:6.66=2:1.
Hence, the law of multiple proportions is illustrated.
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