Question

Two oxides of metal contain 25.8 percent and 41.02 percent of oxygen by mass respectively. Find the ratio of the masses of metal combining with a fixed mass of oxygen

Answer 1

For Oxygen, we can calculate as w(%) = 100 -70 = 30

But Ar(O) = 16

Based on the law of proportion - [% / Ar], so according to it,

= 70/x : 30/16 = 2:3

= 70/x : 1.875 = 2:3, where x = 56 (Fe)

So, if w(O) = 100 – 72.4 = 27.6 (%)

=72.4/56 : 27.6/16 = 1.2928 : 1.725 = 1 : 1.334 = 3 : 4

The answer should be - M3O4 (Fe3O4) . 

Answer 2

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Two metallic oxides contain 27.6%and30% oxygen respectively.if the formula of ...

Then the ratio of weight of oxygen that combines with fixed weight of the metal in the two oxide will be?

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