Question

two oxides of Nitrogen contain the following percentage compositions oxide contains 63.6 4% is nitrogen and 36.3 6 percentage oxygen oxide B contains 40 6.67% in nitrogen and 53.3 3% is Oxygen establish the law of multiple proportion

Answer 1

Answer: Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a fixed mass of the other element are present in the ratios of small whole number.

In the two oxides of nitrogen

Oxide 1: Mass of nitrogen = 63.64 g

Mass of oxygen = 36.36 g

Oxide 2: Mass of nitrogen = 46.67 g

Mass of oxygen = 53.33 g

Thus let us fix the mass of nitrogen:

If 46.67g of nitrogen is combining with 53.33 g in oxide 2

Then 63.34 g of nitrogen will combine with $=\frac{53.33}{46.67}\times 63.64=72.72g$

As, the mass of nitrogen is fixed, so the mass ratio of oxygen in both the compounds must be in whole number ratio.

Mass ratio of oxygen in both the compounds =$\frac{72.72}{36.36}=2$

Hence, these two compounds obeys Law of multiple proportions.

Answer 2

Answer:

answer is 1:2

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