Question

Two oxides the metal contains 78.7%and 64.5% metal respectively if the formula is 1st oxide is Mo find the formula of the second oxide​

Answer 1

Explanation:

Given that, formula of first oxide=M

3

O

4

Let mass of the metal = x

% of metal in M

3

O

4

=

3x+64

3x

×100

But as given % age =(100−27.6)=72.4%

so,

3x+64

3x

×100 = 72.4

or x=56.

In 2nd oxide,

Given, oxygen = 30%, So metal = 70%

So, the ratio is

M:O=

56

70

:

16

30

⟹1.25:1.875

⟹2:3

So, 2nd oxide is M

2

O

3

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