Question

Two painters were painting a house. X finished
his work in 10 days. The same amount of
work was done by Painter Y in 12 days.
How much more work does Painter X do in
a day than Painter Y?​

Answer 1

Two painters i.e. X and Y were painting a house.

X finished his work in 10 days.

Work done by X painter to paint the house in one day = 1/10 part of the work

On the other hand painter Y finished his work in 12 days.

Therefore,

Work done by painter Y in one day = 1/12 part of the work

We have to find the that how much work does painter X do in one day than that of painter Y.

So, to find the work done painter X in one day than that of painter Y. We have to subtract the work done by painter Y from painter X.

i.e.

→ 1/10 - 1/12

Take LCM of 10 and 12 i.e. 60

→ (6 - 5)/60

→ 1/60

Therefore,

The work which is done by painter X than that of painter Y in one day is 1/60 part of the work.

Answer 2

||✪✪ QUESTION ✪✪||

Two painters were painting a house. X finished

his work in 10 days. The same amount of

work was done by Painter Y in 12 days.

How much more work does Painter X do in

a day than Painter Y?

|| ✰✰ ANSWER ✰✰ ||

Let us assume That Total work done is = 60 units . ( LCM).

Given That, X finished his work in 10 days.

So,

→ Efficiency of X = Total work / Total No. of days.

→ Efficiency of X = (60/10)

→ Efficiency of X = 6 unit / day.

Also, Given That, Y finished his work in 12 days..

So,

→ Efficiency of Y = Total work / Total No. of days.

→ Efficiency of Y = (60/12)

→ Efficiency of Y = 5 unit / day.

So, much more work does Painter X do in a day than Painter Y = ( 6 - 5) = 1 unit / day.

→ This work in Fraction now, with Total work = (1/60) unit /day.

Hence, Painter X do (1/60) unit of more work do Per day than Y.