Question

two paper screens A and B are separated by a distance of 100 M A bullet pierces screen A and then screen B .the whole in B is 10 cm below in A if the bullet is travelling horizontally then its velocity at A is

Answer 1

Let x = 100 m and h = 10 cm

Using equation of motion we can then calculate the time of the motion as, 

h = ut + 1/2 gt²

So we will then assume initial velocity to be zero and g = 10 m/s² 

We will get 

t = √2h/g

t = √2 x 10 cm/ 10 m/s²

 t = √2 x 0.1 m / 10m/s²

t = 0.14 s 

Now again we will use equation of motion as, 

x = vt or v = x/t

we get, 

v = 100 m/0.14 s
v = 707.11 m/s

Answer 2

Answer:

707.11

Explanation:

Let x = 100 m and h = 10 cm

Using equation of motion we can then calculate the time of the motion as, 

h = ut + 1/2 gt²

So we will then assume initial velocity to be zero and g = 10 m/s² 

We will get 

t = √2h/g

t = √2 x 10 cm/ 10 m/s²

 t = √2 x 0.1 m / 10m/s²

t = 0.14 s 

Now again we will use equation of motion as, 

x = vt or v = x/t

we get, 

v = 100 m/0.14 s

v = 707.11 m/s