two parallel chord of lengths 80 cm and 18 cm are drawn on the same side of the of the centre of a circle of radius 41 cm. find the distance between the chords.
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AE =40cm
CF=9cm
using Pythagoras theorem in triangle AEO
AO2=AE2+EO2
(41)2=(40)2+EO2
1681=1600+EO2
1681-1600=EO2
81=EO2
9=EO
using Pythagoras theorem in triangle OCF
OC2=CF2+OF2
1681=(9)2+OF2
1681=81+OF2
1681-81=OF2
1600=OF2
40=OF
OC=40-9
OC=31cm
CF=9cm
using Pythagoras theorem in triangle AEO
AO2=AE2+EO2
(41)2=(40)2+EO2
1681=1600+EO2
1681-1600=EO2
81=EO2
9=EO
using Pythagoras theorem in triangle OCF
OC2=CF2+OF2
1681=(9)2+OF2
1681=81+OF2
1681-81=OF2
1600=OF2
40=OF
OC=40-9
OC=31cm
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