Question

Two parallel chords are drawn in a circle of
diameter 30.0 cm. The length of one chord is
24.0 cm and the distance between the two
chords is 21.0 cm; find the length of the other
chord.​

Answer 1

Answer:

d1=v15^2-12^2 =v8 I=9

d2=2 I-9=12 cm

Length of 2nd chord=2v 15^2-12^2

= .2x9=18cm

Answer 2

Answer:

length of other chord = 18 cm

Step-by-step explanation:

two parallel chords are drawn in a circle of diameter 30 cm

=> Radius = 15 cm

Distance between Chords  are  21 cm

Distance between Chords  21 > 15 (Radius)

=> Chords are on different sides of a partcular diameter

Let say Perpendicular distance of chord of 24 cm length from center  = x

then Perpendicular distance of other chord  = 21 - x

Perpendicular from center at chord bisect the chord

=> 15² - (24/2)²   = x²

=> 225 - 144 = x²

=> 81 = x²

=> x = 9

21 - x = 21 - 9 = 12

=>  15²  - 12²  = (Other Chord/2)²

=> 225  - 144 = (Other Chord/2)²

=> 81 = (Other Chord/2)²

=> 9 = Other Chord/2

=> Other Chord = 18 cm

length of other chord = 18 cm

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