two parallel chords are drawn in a circle of diameter 30.0 cm . The length of one chord is 24.0cm and the distance between the two chords is 21.0cm find the length of the other chord
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Let the first chord=24 cm
Second chord=x cm
Radius=Diameter/2
=30cm/2
=15cm
Note that half of first chord,half of second chord and the radius form a right angle triangle with the radius as the hypotenuse
Using Pythagorean theorem
[Half of first chord]^2+[Half of second chord]^2=Radius^2
12^2+[Half of second chord]^2=15^2
144+[Half of second chord]^2=225
[Half of second chord]^2=225-144
[Half of second chord]^2=121
[Half of second chord] =121^1/2
[Half of second chord] =11
So Answer Is 11
Second chord=x cm
Radius=Diameter/2
=30cm/2
=15cm
Note that half of first chord,half of second chord and the radius form a right angle triangle with the radius as the hypotenuse
Using Pythagorean theorem
[Half of first chord]^2+[Half of second chord]^2=Radius^2
12^2+[Half of second chord]^2=15^2
144+[Half of second chord]^2=225
[Half of second chord]^2=225-144
[Half of second chord]^2=121
[Half of second chord] =121^1/2
[Half of second chord] =11
So Answer Is 11
Googol:
sorry there is a calculation mistake in ans
instead of 121 it should be 81 so correct answer is 9 not 11
Answered by
2
the answer is 11.......
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