Question

Two parallel chords are drawn in a circle of Diameter 30 cm. The length of one chord is 24 cm and the distance between the two chords is 21 cm, find the length of other two chords.
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Answer 1

AD=Diameter=30 cm

CD=Chord=24 cm

x+y=21

Again, y

2

+12

2

=15

2

⇒y

2

=15

2

−12

2

⇒y

2

=81

⇒y=9

x=21−9=12

Now, 12

2

+a

2

=16

2

a

2

=16

2

−12

2

=81

⇒a=9

Length of the chord AB=2×9=18cm

Answer 2

Answer:

• The diameter of a circle is 30 cm
• then,the radius is 30/2
• the radius is 15 cm
• the length of one cord is 24 cm
• we ,can find the distance between diameter and the cord is 30 -24 =6
• that means, the radius is 15 cm so,15-6 =9cm
• the distance between the two Cord's is 21 cm ,radius is 15cm ,the distance between diameter and first coard is 6 cm
• so,6+(x) =21
• (x)= 21-6
• (x)= 15
• the distance between diameter and second coard is 15 cm ,radius is also 15 cm
• that means the point is lieying on the circle