Question

two parallel chords of length 14 cm and 48 cm lie on opposite sides of the center of the circle and the distance between the two chords is 31 cm . find the radius of the circle

Answer 1

Answer:

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Step-by-step explanation:

Given- AB=14 cm and CD=48 cm are the chords of a circle of radius 25 cm with centre at O.

OP⊥AB at M and OQ⊥CD at N.

To find out -

If the length of PQ=?

Solution-

We join OC and OA.

So, OC=OA=25 cm, since OC and OA are radii

ΔOAP and ΔOCQ are right ones, since OP⊥AB at P and OQ⊥CD at Q.

Now AP=

2

1

AB=

2

1

×14 cm =7 cm and

CQ=

2

1

CD=

2

1

×48 cm =24 cm