Question

Two parallel chords of lengths 80 cm and 18 cm are drawn on the same side of the centre of the circle of radius 41cm . Find the distance between the chords

Answer 1

let x be the distance
x=√(41²-9²) - √(41²-40²) = 40-9 = 31cm

Answer 2

answer:

AE=40CM

CF=9CM

USING PYTHAGORAS THEOREM IN ∆ AED

AO²=AE²+EO²

=>(41)²=(40)²+EO²

=>EO²=(41)²-(40)²

=>EO²=1681-1600

=>EO²=81

=>EO=√81

=>EO=9

-SIMILARLY WE CAN DO IN ∆ OCF

OF = 40

: OC = 40 - 9

=> OC = 31 CM