Question

Two parallel conductor each of length 5m are placed at a distance of 10cm apart in air. The carry same
currents along the same direction. They experience an attractive force of 3.6x10-N. Calculate the
current flowing through the conductor
a) 3A
b) 6A
c) 9A
d) 12 A​

Answer 1

Answer:

Explanation:The force between the current carrying conductors is given by:

F=  

2πa

μ  

0

​

I  

1

​

I  

2

​

l

​

             

Now, ∵I  

1

​

=I  

2

​

,

I  

2

=  

μ  

0

​

l

F×2πa

​

 

 =  

4π×10  

−7

×5

3.6×10  

−4

×2π×10×10  

−2

 

​

 

I  

2

=36

∴I=6A