Physics, asked by mrdevil9183, 4 months ago

Two parallel conductors carrying current 2A and 4A in the same direction and are separated by a distance 10 cm. Find the magnitude and nature of the force?​

Answers

Answered by listonfdo
1

Answer:

Given,

Current I1=2A, I2=4A

Two wires are separated by a distance a = 1 cm =10×10−2m

Force between two parallel wires per unit length F = ?

F=μ0/2π. I1*I2/a

=2×10−7 ×2 × 4/(10*10^-2) N

F=16×10^-6 N.

This magnitude of the force is repulsive.

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