Physics, asked by sriniwaas4399, 1 year ago

Two parallel light rays passes through an isosceles prisn of refractive index sqrt(3/2) the angle between the two emergent rays is

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Answered by techtro
7

let ∠i denote incidence angle and ∠r denote refracted angle. Given:

∠i=2∗∠r

Now by Snell’s Law applying at interface of Prism:

i1= 1st incident angle

i2=2nd refracting angle on the 2nd prism surface

L1=1st refracting angle

L2=2nd incident angle on the 2nd prism surface

A= Prsim angle=L1+L2

Where we have used trignometric identity in the given picture.

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