Two parallel lines / and m are intersected by a transversal p
see Fig. 8.15). Show that the quadrilateral formed by the bisectors of interior angles
is a rectangle
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the quadrilateral B is making 90° right angle and the opposite D is also making 90° and A and C is 45°
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Answer:
Solution:
It is given that p q and l m
To prove:
Triangles ABC and CDA are similar i.e. ΔABC ΔCDA
Proof:
Consider the ΔABC and ΔCDA,
(i) BCA = DAC and BAC = DCA Since they are alternate interior angles
(ii) AC = CA as it is the common arm
So, by ASA congruency criterion, triangle ABC triangle CDA.
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