Two parallel lines and m cut by a transversal p. If the interior angles on the same side of transversal are 3x0 and 2x0. Find the measures of these angles.
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Answers
Answer:
Two parallel lines l and m be cut by a transversal t, forming angles. It is given that the interior angles of the same side of t be (2x – 8)° and (3x – 7)°. Let the interior angles of the same side of t be, ∠3 = (2x – 8)° and ∠4 = (3x – 7)° We know that the sum of the consecutive interior angle is 180° Then, ∠3 + ∠4 = 180° = (2x – 8) + (3x – 7) = 180 = 2x – 8 + 3x – 7 = 180 = 5x – 15 = 180 = 5x = 180 + 15 = 5x = 195 = x = 195/5 = x = 39 Now substitute the value x in the given equation to get the ∠3 and ∠4 ∴ ∠3 = (2x – 8) = ((2 × 39) – 8) = (78 – 8) = 70° ∠4 = (3x – 7) = ((3 × 39) – 7) = (117 – 7) = 110
Answer:
hi friend
here's your answer looking for
if two angle are 3x and 2x
then ,
3x + 2x = 1803x+2x=180
5x = 1805x=180
\begin{gathered}x = \frac{180}{5} \\ \\ x = 36\end{gathered}
x=
5
180
x=36
so,
angle are
3x = 3×36= 108
2x = 2×36 = 72
hope you are satisfied with my answer