two parallel lines l and m are cut by a transversal t. If the interior angles of the same side of t be (2x-8) degree and (3x-7) degree. Find the measure of each of these angles
Answers
Answered by
658
Hi ,
( 2x- 8 ) and ( 3x - 7 ) are interior angles of the
same side of the transversal .
we know that ,
sum of interior angles of same side of the
transversal = 180°
2x - 8 + 3x - 7 = 180
5x - 15 = 180
5x = 180 + 15
5x = 195
x = 195 / 5
x = 39
Therefore ,
2x - 8 =( 2 × 39 ) -8
= 78 - 8
= 70°
3x - 7 = ( 3 × 39 ) - 7
= 117 - 7
= 110°
I hope this helps you ,
:)
( 2x- 8 ) and ( 3x - 7 ) are interior angles of the
same side of the transversal .
we know that ,
sum of interior angles of same side of the
transversal = 180°
2x - 8 + 3x - 7 = 180
5x - 15 = 180
5x = 180 + 15
5x = 195
x = 195 / 5
x = 39
Therefore ,
2x - 8 =( 2 × 39 ) -8
= 78 - 8
= 70°
3x - 7 = ( 3 × 39 ) - 7
= 117 - 7
= 110°
I hope this helps you ,
:)
Answered by
96
Answer:
3x minus 10 is equal to 5 x minus 13 - 10 + 30 is equal to 5 x minus 3 x 20 is equal to 2 x 20 divided by 2 is equal to x is equal to 10 x
Step-by-step explanation:
ab is parallel to CD angle 1 is equal to 3 x minus 10 3 x x minus 10 is equal to 20 degree angle 1 is equal to 20 degree
7 is equal to 5 x minus 35 x x 10 minus 30 is equal to 20 degree
Similar questions