Two parallel lines l and m cut by a transversal 't' . If the interior angles on the same side on transversal are (2x-8°) and (3x-7°) . find the measure of each of these angles
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Answered by
37
2x - 8° + 3x - 7° = 180
5x - 15 = 180
5x = 195
x = 39°
Hence the angles measures are
2x - 8= 70°
and, 3x - 7 = 110°
5x - 15 = 180
5x = 195
x = 39°
Hence the angles measures are
2x - 8= 70°
and, 3x - 7 = 110°
Answered by
18
2x-8+(3x-7) = 180 (Co Interior Angles)
5x-15 = 180
5x = 195
x = 195 ÷ 5
x = 39
2x-8 = 2×39-8 =70
3x-7= 3×33-7 = 110
5x-15 = 180
5x = 195
x = 195 ÷ 5
x = 39
2x-8 = 2×39-8 =70
3x-7= 3×33-7 = 110
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