Question

Two parallel metal plates each having area 10 m² and separated by a distance of 1 cm carry
charges +Q and -Q respectively. A test charge placed between them experience a force F. Now the
separation between the plates is doubled, then the force on the test charge will be ...​

Answer 1

Dear students,

◆ Answer -

F' = F/4

● Explanation -

# Given -

A = 10 m^2

r = 1 cm

r' = 2r

charges = +Q, -Q

# Solution -

Let F be initial force acting on the test charge & F' be that after doubling the distance between plates.

Force acting on the charge is inversely proportional to square of distance between plates.

F/F' = (r'/r)^2

F/F' = (2r/r)^2

F/F' = 4

F' = F/4

Therefore, force acting on the test charge is F/4.