Question

two parallel plane mirrors M1 and M2 have a length of 2 metre each and at 10:00 millimetre apart A Ray of light is incident on one end of mirror M2 at an angle 30 degree the number of reflections light undergoes before reaching the other end is​

Answer 1

Answer: there are 57.73 number of reflections light undergoes before reaching the other end

Explanation:

Given that:

There are two parallel plane mirrors M1 and M2.

Length of mirror = 2 metre

Distance between mirrors = 10mm

One Ray of light is incident on one end of mirror M2.

Angle = 30°

To find:

the number of reflections light undergoes before reaching the other end =?

Solution

It is given that the two mirrors are parallel

The light is incident on the second mirror M2 from M1 using angle 30°

We can assume that the mirror length can be given as tan theta.

It is perpendicular length and we will denote it by L

Theta = 30°

Tan 30 = 1/L

1/√3 = 1/L

Hence L = √3 cm

This is for one reflection

Hence, for 1 m length, the number of reflections will be

1m = 100cm

For 100 cm

The number of reflections will be

= 100/√3

= 57.73

Hence,

there are 57.73 number of reflections light undergoes before reaching the other end.

Answer 2

Answer:346

Explanation: