Question

two parallel plate capacitors of capacitance c and 2c are connected in parallel and charged to a potential difference v . if the battery is disconnected and the space between the plates of the capacitor of capacitance c is completely filled with a material of dielectric const. k then pot. diff. across the capacitor will be come (A) 3v(k+2) (B) (K+2)/ 3v (C) 3v/(k+2) (D) 3(k+2)/ v

Answer 1

The potential difference across the capacitor will become

V'= 3*V/(K+2)

Option (C) is correct.

Explanation:

Since the total charge that have appeared before and after removing the battery is same.

Original charge= (2 x C + C) x V as the capacitors are connected in parallel.

After removing the battery:

New capacitance = (K x C + 2 x C) x V'.

Where V' is the final potential difference.

After equating we get:

V'= 3*V/(K+2)  

Thus the potential difference across the capacitor will become

V'= 3*V/(K+2)  

Also learn more

A current of 0.5 A is drawn by a filament of an electric bulb for 10 min. find the amount of electric charge that flows through the current?

https://brainly.in/question/78712