Physics, asked by Jenengapik4095, 10 months ago

Two parallel plate capacitors of capacitances C and 2C are
connected in parallel and charged to a potential difference V.
The battery is then disconnected and the region between the
plates of the capacitor C is completely filled with a material fo
dielectric constant K. The potential difference across the
capacitors now becomes
(a)3V/K + 2 (b) KV (c)V/K (d)3/KV

Answers

Answered by girdharhitesh05
1

Answer:

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