Physics, asked by onlineclasses648, 5 hours ago

Two parallel plates 5.0 cm apart are oppositely charged. The electric potential difference across the plates is 80.0 V. (a) What is the magnitude & direction of electric field intensity between the plates? What is the potential difference between points A and B & which point is at higher potential?

Answers

Answered by sushil19gupta

Answer:

The electrical potential difference in a uniform electric field is given as V=Ed. The work done moving a charge against the field can be found by W=Vq.

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