Two parallel plates 5.0 cm apart are oppositely charged. The electric potential difference across the plates is 80.0 V. (a) What is the magnitude & direction of electric field intensity between the plates? What is the potential difference between points A and B & which point is at higher potential?
Answers
Answered by
1
Answer:
The electrical potential difference in a uniform electric field is given as V=Ed. The work done moving a charge against the field can be found by W=Vq.
Similar questions
Math,
3 hours ago
Computer Science,
3 hours ago
Hindi,
7 months ago
English,
7 months ago
Math,
7 months ago