Question

Two parallel plates have a potential
difference of 10V between them. If the
plates are 0.5 mm apart, what will be the
strength of electric charge.
​

Answer 1

Answer:

The strength of electric charge is $2\times10^{4}\ V/m$

Explanation:

Given that,

Potential difference = 10 V

Distance = 0.5 mm

We need to calculate the strength of charge

Using formula of electric field

$E=\dfrac{V}{d}$

Where, V = potential difference

d = distance

Put the value into the formula

$E=\dfrac{10}{0.5\times10^{-3}}$

$E=20000\ V/m$

$E=2\times10^{4}\ V/m$

Hence, The strength of electric charge is $2\times10^{4}\ V/m$