Question

Two parallel plates having equal but opposite charges are separated by a dielectric slab 2 cm
thick, with dielectric constant 3. If the electric field strength between the plates is 10^6V/m,
calculate the displacement vector and polarisation vector​

Answer 1

Answer:

Dielectric constant:−

K=

E

E

0

=

1×10

5

2×10

5

=2

Hence,

option (A)is correct

Answer 2

Answer:

• polarisation vector = XeEoE = 3× 8.85 × 10^-12 × 10^ 4= 26. 55× 10^ -8
• displacement vector = EoE + P = 8.85× 10^-12× 10^4 + 3× 10^4 × 8.85× 10^ - 12 = 35. 4 × 10^ -8

Explanation:

Electric polarization vector",is related with the electromagnetism phenomenon of the physics. It means that the vector field that denotes the dipole moment of every single dielectric materials which is using in the electro magnetic field or using simply as the electricity conductor.

the electric displacement, also known as dielectric displacement and usually denoted by its first letter D, is a vector field in a non-conducting medium, a dielectric. The displacement D is proportional to an external electric field E in which the dielectric is placed.