two parallel rail tracks run north -south. train A moves north with speed 54km/h and train B moves south with speed 90km/h. what is the velocity of a monkey running on roof of a train A against its motion (with velocity of 18km/h with respect to A)as observed by a man standing on ground(in m/s).
Answers
Solution -
Velocity of Monkey with respect to ground is – VM
Velocity of Monkey with respect to train A is - VA
Relative velocity of Monkey with respect to train A - VMA
VMA = VM - VA
Given - Velocity of Monkey with respect to train A = VA = 54 Km/h = 54 x 5/18 m/s = 15 m/s
And Relative velocity of Monkey with respect to train A = VMA = -18 Km/h = -18 x 5/18 = -5 m/s
(as monkey running against the motion)
Therefore,
VMA = VM - VA
-5 m/s = VM – 15 m/s
VM = -5 m/s + 15 m/s
VM = 10 m/s
Answer - The velocity of a monkey running on roof of a train A against its motion is 10 m/s
Answer:
Explanation:
a. vBA
= vB
- vA
Hence, velocity of train B w.r.t train A is 144 km/h toward south.
b. Velocity of ground w.r.t. B
vg,B=vg−vB = 0 - 90$$
vg,B = -90 km/h
Hence, velocity of ground w.r.t train B is 90 km/h towards north.
c. vm,g
= vm,A
+ vAg
= 18 - 54 = -36 km/h
Hence, velocity of monkey will be 36 km/h toward north