Question

Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and
26cm. Find the area of the trapezium.

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Answer 1

Answer:

Step-by-step explanation:

→ Draw a line BC parallel to AD 

→ Draw a perpendicular line BE on DF

→ ABCD is a parallelogram.

→ BC=AD=25cm

→ CD=AB=60cm

→ CF=77-CD=17cm

→ For Δ BCF

⇒ perimeter of triangle=(25+26+17)/2

=68/2=34

⇒ By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)

=√34(34-25)(34-26)(34-17)

=204cm²

⇒ Now area of ΔBCF=1/2xbase x height

=1/2 BExCF204cm²

=1/2x BEx17BE

=408/17

=24cm

⇒ Area of Trapezium =1/2(AB+DF)xBE

=1/2(60+77)x24

=1644cm²

Answer 2

Answer:

first side = 60

second side=77

third side =25

fourth side = 26

formula of trapezium = 4side plus

=26 +25+70+60

=181