two parallel side of an isoscles trapazium are 6cm and 14cm respectively. If the length of eah non-parallel side is 5cm find area of trapazium
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Ar of rhombus =1/2*6+14*5
=1/2*20*5
=150cm
=1/2*20*5
=150cm
Answered by
1
First find height.
Height = 5²-4²= 3² .
Here, The trapezium forms a right angled triangle at the edge .It follows a Pythagoras theorem .
Now. Area of trapezium = 1/2( Sum of parallel sides )( Height)
= 1/2(14+6)(3)
=1/2(20)(3)
= 30cm²
Height = 5²-4²= 3² .
Here, The trapezium forms a right angled triangle at the edge .It follows a Pythagoras theorem .
Now. Area of trapezium = 1/2( Sum of parallel sides )( Height)
= 1/2(14+6)(3)
=1/2(20)(3)
= 30cm²
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