Question

Two parallel sides DC and AB of a trapezium are 12cm and 36 cm respectively. If non parallel sides are each eqiual

to 15cm, find the area of the trapezium.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

➩Given:

(i) ABCD is a Trapezium

where DC||AB

(ii) AD=CB=15cm

(iii) DC=12cm

(iv) AB=36cm

➩To Find:

The Area of the Trapezium ABCD

➩ Solution:

If DC||AB (given)

then DC||AE (parts of parallel lines)

Draw a line CE||AD

Now

AD||CE

DC||AE

Thus, AECD is a Parallelogram.

AD=CE (Opposite sides of parallelogram are always equal)

∴CE=15cm

Similarly,

DC=AE (Opposite sides of parallelogram are always equal)

∴AE=12cm

AE+EB=36cm

12+EB=36

EB=36-12

EB=24cm

Draw an Altitude CF⊥EB (Construction)

EF=FB (when an Altitude falls on a line ,it besects it or divide it into two equal parts)

EF+FB=24

FB+FB=24(as EF=FB)

2FB=24

$FB = \frac{24}{2}$

FB=12cm

Now in △CFB

we can use Pythagoras theorem as ∠CFB=90°

${(CB)}^{2} = {(FB)}^{2} = {(CF)}^{2}$

${(15)}^{2} = {(12)}^{2} = {(CF)}^{2}$

$225 = 144 = {(CF)}^{2}$

$225 - 144 = {(CF)}^{2}$

$81= {(CF)}^{2}$

$\sqrt{81} = CF$

CF=9cm

Also CF is the Height of the Trapezium ABCD

Area of Trapezium=

$\frac{1}{2} ×Height×(Sum \: of \: parallel \:sides)$

$= \frac{1}{2} ×9×(12+36)$

$= \frac{1}{2} ×9×48$

$=9×24$

$= {(216)}cm^{2}$