Question

Two parallel sides of a trapezium are 120cm and 154cm and the other sides are 50cm and 52 cm. Find the area of the trapezium..

Answer 1

Answer:

Step-by-step explanation:Let ABCD be the trapezium with AB = 154 cm, BC = 52 cm, CD = 120 cm and AD = 50 cm Complete parallelogram AECD Hence CE = 50 cm and AE = 120 cm Draw CF⊥BC From the figure BE = AB – AE Þ BE = 154 – 120 = 34 cm First we will find the area of ΔCEB using Heron’s formula Here a = 50 cm, b = 52 cm and c = 34 cm Hence area of ΔCEB = 816 sq cm Area of triangle = 816 = (1/2) × 34 × CF Hence CF = 48 cm Area of parallelogram AECD = AE × CF = 120 × 48 = 5760 sq cm Hence area of trapezium ABCD = area of parallelogram AECD + area of ΔCEB = 5760 + 816 = 6576 sq cm

Answer 2

Answer:

Step-by-step explanation:

Answer:

The area of the trapezium is 6576 cm square.

Step-by-step explanation:

Given : Two parallel sides are 120cm and 154cm and other sides 50cm 52cm

To find : Area of trapezium?

Solution :

Area of the triangle,

Area of the trapezium is

Therefore, The area of the trapezium is 6576 cm square.