Two parallel sides of a trapezium are 120cm and 154cm and other sides are 50cm and 52cm. Find the area of the trapezium
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Answer:
6576 cm²
Step-by-step explanation:
Area of ΔDOC = √s(s-a) (s-b) (s-c) [using heron's formula]
[s = 50+52+34/2 = 68 cm]
= √68(68-50)(68-52)(68-34)
= √68 × 18 × 18 × 34
= 816 cm²
Also, Area of a triangle = 1/2 × bh
=> 1/2 × 34h = 816 cm²
=> h = 48 cm
Area of trapezium ABCD = 1/2 h(AD + BC) = 1/2 × 48 (120+154)= 6576 cm²
Hope that helps.
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srinivasc1905:
Thanks a loy
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