Question

Two parallel sides of a trapezium are 1m and 2m respectively and the perpendicular distance between them is 6m. Then find the area of trapezium.

Answer 1

Hi there !

$area \: of \: trapezium \\ = \frac{1}{2} h(a + b)$
where h is the height

and

a and b are the sum of parellal sides.


$area \: = \frac{1}{2} \times 6(1 + 2)m$

$area \: = \frac{1}{2} \times 6 \times 3m$
= 9m²


Thus,

The area of trapezium is 9m².

Answer 2

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