Question

two parallel sides of a trapezium are 60cm and 77cm and other sides are 25cm and 26cm. find the area of the trapezium.

Answer 1

Draw a line BC parallel to AD 
Draw a perpendicular line BE on DF
ABCD is a parallelogram.
BC=AD=25cm
CD=AB=60cm
CF=77-CD=17cm

For Δ BCF
perimeter of triangle=(25+26+17)/2
=68/2=34
By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)
=√34(34-25)(34-26)(34-17)
=204cm²

Now area of ΔBCF=1/2xbase x height
=1/2 BExCF204cm²
=1/2x BEx17BE
=408/17
=24cm

Area of Trapezium =1/2(AB+DF)xBE
=1/2(60+77)x24
=1644cm²

Answer 2

Step-by-step explanation:

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