Question

two parallel sides of a trapezium aur of length 27 CM under 19 CM respectively and the distance between them is 14CM then the area of trapezium is​

Answer 1

Answer:

322is a answer.please mark in brainlist

Step-by-step explanation:

1/2×(27+19)×14

1/2×46×14

7×46

322

Answer 2

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Here Parallel Sides area a

$A= 7 \: cm \: \\ \: B = 19 \: cm \: \\ \: h \: = 14 \: cm$

Area of Trapezium

$= \frac{1}{2} \times (a + b) \times h$

$= \frac{1}{2} \times( 27 + 19) \times 14$

$= 46 \times 7 = 322sq. \: cm$

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