Question

Two parallel sides of an isoceles trapezium are 12and 20 cm respectively.If the length of each non-parallel side is 10cm find the area of the trapezium

Answer 1

hey there !!

let the trapezium be ABCD where AB and CD are the parallel sides.

Now,

AB=6 cm

CD=14 cm

AD=BC=5 cm

Construct a line parallel to BC from A to a point E on DC.

NOw, ar(ADE)= 12 sq. cm (By Heron's Formula)

ar(ADE)= 1/2*b*h

Therefore the height is 6 cm.

ar(ABCE)= b*h

=6cm*6cm

=36 sq.cm

Hence, area of ABCD is=12+36 i.e. 48 sq. cm.

Answer 2

mark as brainliest this is the answer